If MACHINE is coded as $19 - 7 - 9 - 14 - 15 - 20 - 11$ , how will you code DANGER?

10 - 7 - 20 - 13 - 11 - 24

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11 - 7 - 20 - 16 - 11 - 24

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13 - 7 - 20 - 9 - 11 - 25

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13 - 7 - 20 - 10 - 11 - 25

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None of these

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Solution

The correct option is A $10 - 7 - 20 - 13 - 11 - 24$
Given, MACHINE is coded as $19 - 7 - 9 - 14 - 15 - 20 - 11$ .
Here, every letter is assigned a numerical code obtained by adding $6$ to the numeral denoting the position of that letter in the English alphabet.
E.g, A is coded as $1 + 6 = 7$ , M is coded as $13 + 6 = 19$ .
Similarly, the position of letter D, A, N, G, E and R is $4 t h, 1 s t, 14 t h, 7 t h, 5 t h$ and $18 t h$ respectively in the English alphabet.
So, DANGER is coded as $10 - 7 - 20 - 13 - 11 - 24$ .
Hence, option (A) is the correct answer.

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Similar questions

if a machine is coded as 19-7-9-14-15-20-11 so what is danger coded as?

Find each of the following products :

(i) $\frac{3}{5} \times \frac{- 7}{8}$ (ii) $\frac{- 9}{2} \times \frac{5}{4}$ (iii) $\frac{- 6}{11} \times \frac{- 5}{3}$

(iv) $\frac{- 2}{3} \times \frac{6}{7}$ (v) $\frac{- 12}{5} \times \frac{10}{- 3}$ (vi) $\frac{25}{- 9} \times \frac{3}{- 10}$

(vii) $\frac{5}{- 18} \times \frac{- 9}{20}$ (viii) $\frac{- 13}{15} \times \frac{- 25}{26}$ (ix) $\frac{16}{- 21} \times \frac{14}{5}$

(x) $\frac{- 7}{6} \times 24$ (xi) $\frac{7}{24} \times (- 48)$ (xii) $\frac{- 13}{5} \times (- 10)$

20

5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20

20

5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20

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