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Question

# If mass and radius of the Earth are 6.0×1024 kg and 6.4×106 m respectively, calculate the force exerted by the Earth on a body of mass 1 kg. Also, calculate acceleration produced in the body of mass 1 kg and acceleration produced in the Earth. The accelerations of 1 kg mass and Earth are:

A

9.8 ms2 and 1 ms2 respectively

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B

9.8 ms2 and 1.63×1024 ms2 respectively

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C

1.63×1024 ms2 and 9.8 ms2 respectively

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D

9.8 ms2 for both

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Solution

## The correct option is B 9.8 ms2 and 1.63×10−24 ms2 respectively From Newton's law of gravitation, we know that the force of attaraction between the bodies is given by: F = Gm1m2r2 Here, m1 = mass of Earth = 6.0×1024 kg and m2 = mass of the body = 1 kg r = distance between the two bodies = radius of the Earth = 6.4×106 m G = 6.67×10−11 Nm2kg2 F = 6.67×10−11×6.0×1024×1(6.4×106)2 = 9.8 N This shows that Earth exerts a force of 9.8 N on a body of mass 1 kg. The body will exert an equal force of attraction of 9.8 N on the Earth. Accelaration produced in the body of mass 1 kg: Force = mass × acceleration Therefore, Acceleration, a = Fm = F1 = 9.8 ms2 Thus, the acceleration produced in a body of mass 1 kg due to attraction of the Earth is 9.8 ms2, which is quite large. Thus, when a body is released, it falls towards the Earth with an acceleration of 9.8 ms2, which can be easily observed. Acceleration produced in the Earth: Similarly, acceleration of the Earth is given by ForceMass of Earth = 9.86.0×1024 = 1.63×10−24 ms2 This shows that the acceleration produced in the Earth by a body of mass 1 kg is 1.63×10−24 ms2 which is very small and cannot be observed.

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