Question

If mass (M), velocity (V) and time (T) are taken as fundamental units, then the dimensions of force (F) are

• A. $\left[MVT\right]$
• B. $\left[MV{T}^{-1}\right]$
• C. $\left[M^{2}VT\right]$
• D. $\left[M^{-1}{V}^{-1}T\right]$

Answer 1

The correct option is B $\left[MV{T}^{-1}\right]$

$Force=Mass\times Acceleration=Mass\times \frac{Velocity}{Time}$

That is,

$\left[F\right]=\left[M\right]\times \frac{\left[V\right]}{\left[T\right]}=\left[MV{T}^{-1}\right]$