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Standard XII

Physics

Gravitational Field

If mass of ea...

Question

If mass of earth is $M$ , radius is $R$ and gravitational constant is $G$ , then work done to take $1 k g$ mass from earth surface to infinity will be:

\sqrt{\frac{G M}{2 R}}

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\frac{G M}{R}

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\sqrt{\frac{2 G M}{R}}

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\frac{G M}{2 R}

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Solution

The correct option is C $\frac{G M}{R}$
Since work done is equal to the change in potential energy,
This implies that,

$= [0 - (- \frac{G M m}{R})] = \frac{G M m}{R}$

since, $m = 1 K g$

Thus,

$\frac{G M (1)}{R} = \frac{G M}{R}$

Hence, Option $B$ is the correct answer.

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If mass of earth is M, radius is R and gravitational constant is G, then work done to take 1kg mass from earth surface to infinity will be:

The correct option is C GMRSince work done is equal to the change in potential energy,This implies that,=[0−(−GMmR)]=GMmRsince, m=1KgThus,GM(1)R=GMRHence, Option B is the correct answer.

If mass of earth is $M$ , radius is $R$ and gravitational constant is $G$ , then work done to take $1 k g$ mass from earth surface to infinity will be:

The correct option is C $\frac{G M}{R}$
Since work done is equal to the change in potential energy,
This implies that,

$= [0 - (- \frac{G M m}{R})] = \frac{G M m}{R}$

since, $m = 1 K g$

Thus,

$\frac{G M (1)}{R} = \frac{G M}{R}$

Hence, Option $B$ is the correct answer.