Question

If mass of neutron is assumed to half of its original value, whereas that of proton is assumed to be twice of its original value, then the atomic mass of ${}_6^{14}C$ will be:

• A. same
• B. $14.28\%$ more
• C. $14.25\%$ less
• D. $28.56\%$ less

Answer 1

Answer: (B)

$14.28\%$ more

${}_6^{14}C$

number of proton= 6

number of neutron = 8

mass of proton = 6 amu

mass of neutron = 8 amu

total mass = 6 + 8 = 14

now the mass of neutron s halved so,= 8/2 = 4

the mass of proton is doubles = 6 x2

new mass = 6x2 + 4 = 16 amu

% of increase in mass= 16 -14/ 14 x 100

$=14.28$