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Question

If mass of the electron =9.1×1031 kg, charge on the electron =1.6×1019 C and g=9.8 ms2. Then, the intensity of the electric field required to balance the weight of an electron is -

A
5.6×109 N/C
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B
5.6×1011 N/C
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C
5.6×108 N/C
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D
5.6×107 N/C
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Solution

The correct option is B 5.6×1011 N/C
From equilibrium of forces,

qE=mg

E=mgq

E=9.1×1031×9.81.6×1019

E=5.6×1011 N/C

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