If mass of U235=235.12142amu, mass of U236=236.1205amu, and mass of neutron 1.008665amu, then the energy required to remove one neutron from the nucleus of U236 is nearly about
A
75MeV
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B
6.5MeV
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C
1eV
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D
zero
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Solution
The correct option is B6.5MeV The total mass of U235 and a neutron is M1=235.12142−1.008665=236.130amu
Increases in mass when one neutron is removed from U236=M1−mass of U236