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Standard IX

Chemistry

Neutron

If mass of ...

Question

If mass of $U^{235} = 235.12142 a m u$ , mass of $U^{236} = 236.1205 a m u$ , and mass of neutron $1.008665 a m u$ , then the energy required to remove one neutron from the nucleus of $U^{236}$ is nearly about

75 M e V

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6.5 M e V

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1 e V

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zero

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Solution

The correct option is B $6.5 M e V$
The total mass of $U^{235}$ and a neutron is $M_{1} = 235.12142 - 1.008665 = 236.130 a m u$
Increases in mass when one neutron is removed from $U^{236} = M_{1} -$ mass of $U^{236}$
$= 236.130 - 236.1205 = 0.009 a m u = 0.009 \times 931 M e V = 8.9 M e V \sim 6.5 M e V$

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If mass of U235=235.12142amu, mass of U236=236.1205amu, and mass of neutron 1.008665amu, then the energy required to remove one neutron from the nucleus of U236 is nearly about

The correct option is B 6.5MeVThe total mass of U235 and a neutron is M1=235.12142−1.008665=236.130 amuIncreases in mass when one neutron is removed from U236=M1−mass of U236 =236.130−236.1205=0.009 amu=0.009×931 MeV=8.9 MeV∼6.5 MeV

If mass of $U^{235} = 235.12142 a m u$ , mass of $U^{236} = 236.1205 a m u$ , and mass of neutron $1.008665 a m u$ , then the energy required to remove one neutron from the nucleus of $U^{236}$ is nearly about