Question

If $A=\left[\begin{array}{cc}4& 7\\ 6& 5\end{array}\right],$ $B=\left[\begin{array}{cc}3& 8\\ 7& 2\end{array}\right],C=\left[\begin{array}{cc}8& 11\\ 6& 1\end{array}\right],$ then show that

• A. $A+B=B+A$
• B. $(A+B)+C=A+(B+C)$
• C. $A+O=O+A$
• D. $A+(-A)=(-A)+A=0$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A $A+B=B+A$
B $(A+B)+C=A+(B+C)$
C $A+O=O+A$
D $A+(-A)=(-A)+A=0$