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Question

If ABCDEF be a regular hexagon and ¯¯¯¯¯¯¯¯AB=¯¯¯a, ¯¯¯¯¯¯¯¯BC=¯¯b, ¯¯¯¯¯¯¯¯¯CD=¯¯c then ¯¯¯¯¯¯¯¯AE is equal to

A
¯¯¯a+¯¯b+¯¯c
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B
¯¯b+¯¯c
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C
¯¯¯a+¯¯b
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D
¯¯¯a+¯¯c
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Solution

The correct option is C ¯¯b+¯¯c
(Regular Hexagon )
AE=AB+BC+CD+DE(addition theorem)
DE=AB(anti parllel vector)
AE=b+c
54911_34129_ans.bmp

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