If C and D are two events such that C-D and PD- 0- then the correct statement among the following is

The correct option is D P(CD) ≥P(C) P(C/D)=P(C∩D)/P(D)=P(C)/P(D)≥P(C) (Since 0 lt;P(D)≤ 1 )So, #160;P(C/D)≥P(C) Hence, option 'B' is cor ...

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Byju's Answer

Standard XII

Mathematics

Conditional Probability

If C and ...

Question

If $C$ and $D$ are two events such that $C \subset D$ and $P (D) \neq 0$ , then the correct statement among the following is

P (\frac{C}{D}) = P (C)

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P (\frac{C}{D}) \geq P (C)

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P (\frac{C}{D}) < P (C)

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P (\frac{C}{D}) = \frac{P (D)}{P (C)}

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Solution

The correct option is D $P (\frac{C}{D}) \geq P (C)$
$P (\frac{C}{D}) = \frac{P (C \cap D)}{P (D)} = \frac{P (C)}{P (D)} \geq P (C)$ (Since $0 < P (D) \leq 1$ )
So, $P (\frac{C}{D}) \geq P (C)$
Hence, option 'B' is correct.

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Similar questions

In the following diagram $P_{A}, P_{B}, P_{C}, P_{D} a n d P_{E}$ be the pressure exerted by the liquid in the vessels A, B, C, D and E respectively. Find the correct order of pressure exerted by each vessel.

Q. If

C a n d D

are two events such that

C \subset D

and

P (D) \neq 0

, then the correct statement among the following is:

Q. Figure shows a container filled with a liquid of density

ρ

. Four points

A, B, C

and

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lies on the vertices of a vertical square. Points

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and

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lies on a vertical line and points

B

and

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Q. Figure shows a container filled with a liquid of density

ρ

. Four points

A, B, C and D

lie on the diametrically opposite points of a circle as shown. Points

A

and

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lie on a vertical line and points

B

and

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lie on a horizontal line.

P_{A}, P_{B}, P_{C}, P_{D}

are the absolute pressures at the respective points. Then, the correct statement(s) is/are :

Q. Figure shows a container filled with a liquid of density

ρ

. Four points

A, B, C

and

D

lie on the diametrically opposite points of a circle as shown. Point

A

and

C

lie on vertical and point

B

and

D

lie on horizontal line. The incorrect statement is (

P_{A}, P_{B}, P_{C}, P_{D}

are absolute pressure of the respective points).

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If C and D are two events such that C⊂D and P(D)≠0, then the correct statement among the following is

The correct option is D P(CD)≥P(C)P(CD)=P(C∩D)P(D)=P(C)P(D)≥P(C) (Since 0<P(D)≤1)So, P(CD)≥P(C)Hence, option 'B' is correct.

If $C$ and $D$ are two events such that $C \subset D$ and $P (D) \neq 0$ , then the correct statement among the following is

The correct option is D $P (\frac{C}{D}) \geq P (C)$
$P (\frac{C}{D}) = \frac{P (C \cap D)}{P (D)} = \frac{P (C)}{P (D)} \geq P (C)$ (Since $0 < P (D) \leq 1$ )
So, $P (\frac{C}{D}) \geq P (C)$
Hence, option 'B' is correct.