If h2+k2>a2 , then the number of solutions of the equation hx+ky=a2 and x2+y2=a2 is
A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B2 x2+y2=a2 Given h2+k2>a2 then p(h,k) lies outside circle x2+y2=a2 Then chord of contact from p(h,k) to x2+y2=a2 is xh+yk=a2 So, xh+yk=a2 ⇒ no. of solution of the equation hx+ky=a2 and x2+y2=a2 are 2.