If $\sin x = 0.6$ , what is the value of $\cos x$ ?

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Solution

Find the value of $\cos (x)$ :
Given, the value is $\sin x = 0.6$
It is known that $\sin^{2} (x) + \cos^{2} (x) = 1$ .
Substitute the value of $\sin x = 0.6$ in the above equation:
$\begin{array}{rcl} \sin^{2} (x) + \cos^{2} (x) & = & 1 \\ \Rightarrow {(0.6)}^{2} + \cos^{2} (x) & = & 1 \\ \Rightarrow \cos^{2} (x) & = & 1 - 0.36 \\ \Rightarrow \cos^{2} (x) & = & 0.64 \\ \Rightarrow & \cos (x) = \pm 0.8 \end{array}$
Hence, the value of $\cos (x)$ is $\pm 0.8$ .

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If sinx=0.6, what is the value of cosx?

Find the value of cosx:Given, the value issinx=0.6It is known that sin2x+cos2x=1.Substitute the value of sinx=0.6in the above equation:sin2(x)+cos2(x)=1⇒(0.6)2+cos2(x)=1⇒cos2(x)=1−0.36⇒cos2(x)=0.64⇒cosx=±0.8Hence, the value of cosx is ±0.8.

If $\sin x = 0.6$ , what is the value of $\cos x$ ?