You visited us 1 times! Enjoying our articles? Unlock Full Access!

Evaluating the Given Number

If x= 4 ,y= 3...

Question

If $x = 4$ , $y = 3$ , $z = 1$ then $2 x + y + 1$ is :

$10$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$11$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$12$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$13$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$12$

Justification Of Answer:
Put $x = 4$ , $y = 3$ , $z = 1$ in $2 x + y + 1$ , we get
$2 x + y + 1$ $= 2 \times (4) + 3 + 1$
$= 8 + 3 + 1$
$= 12$
Thus, Option C is the correct answer

Suggest Corrections

Similar questions

α x + y + z = α - 1

x + α y + z = α - 1

x + y + α z = α - 1

α

a

3 x - y + a z

= 1, 2 x + y + z = 2, x + 2 y - a z = - 1

¯ ¯¯ ¯ α = (x + 4 y) a + (2 x + y + 1) b

¯ ¯ ¯ β = y - 2 x + 2) a + (2 x - 3 y - 1) b

b

¯ ¯¯ ¯ α = 2 ¯ ¯ ¯ β = x = 2, y = - 1

D, E, F

B C . C A, A B

Δ A B C

A D + B E + C F = 0

Fill in the blanks :

If $x, y, z$ are three integer, then $(x + y) +$ $(___) = (____) + (____)$

A = (x_{1}, y_{1})

B = (x_{2}, y_{2}), C = (x_{3}, y_{3})

(x - x_{1})^{2} + (y - y_{1})^{2} =

a^{2}

(x - x_{2})^{2} + (y - y_{2})^{2} = a^{2}, (x - x_{3})^{2} + (y - y_{3})^{2} = a^{2}

Join BYJU'S Learning Program