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Question

If zex2+y2=1

then xzx+yzy=?

A
2zlogz
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B
2z
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C
2logzz
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D
2logz
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Solution

The correct option is A 2zlogz

z=e(x2+y2)=ex2y2
logz=(x2+y2)


xzx+yzy=x(ex2y2)(2x)+y(ex2y2)(2y)

=2(ex2y2)(x2+y2)

=2zlogz


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