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Question

If maximum and minimum values of the determinant
∣ ∣ ∣1+cos2xsin2xcos2xcos2x1+sin2xcos2xcos2xsin2xcos2x∣ ∣ ∣ are α and β then

A
α2+β10=10
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B
α3β99=26
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C
2α218β4=0
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D
All the above
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Solution

The correct option is C All the above
Let A=∣ ∣ ∣1+cos2xsin2xcos2xcos2x1+sin2xcos2xcos2xsin2x1+cos2x∣ ∣ ∣
So, By row transformation in A,
r2r2r1 and r3r3r1
A=∣ ∣1+cos2xsin2xcos2x110101∣ ∣
So, A=cos2x(1)+1(1+cos2x+sin2x)
A=2+cos2x
So, max value of A=α=3
and min value of A=β=1
So, α2+β10=9+1=10
α3β99=271=26
2α218β4=1818=0
So, all are true

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