If m C 1- n C 2- thenA- 2 n - m m -1B- 2 m - nC- 2 m - n n -1D- 2 m - n n -1

The correct option is D 2m = n(n 1) 2m = n(n 1) ^mC_1 = ^nC_2 ⇒m!/1! (m 1)! = n!/2! (n 2)! ⇒m(m 1)!/(m 1)! = n(n 1)(n 2)!/2(n 2)! ⇒ 2m = n(n 1) ...

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nCr Definitions and Properties

If m C 1= n C...

Question

If $^{m} C_{1} =^{n} C_{2},$ then

2m = n

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2m = n(n+1)

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2m = n(n-1)

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2n = m(m-1)

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Solution

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Similar questions

1^{2} .^{n} C_{1} + 2^{2} .^{n} C_{2} + 3^{2} .^{n} C_{3} + . . . + n^{2} .^{n} C_{n}

m, n (with n \geq m) =^{n} C_{m}

(\begin{matrix} n m \end{matrix}) + (\begin{matrix} n - 1 m \end{matrix}) + (\begin{matrix} n - 2 m \end{matrix}) + . . . + (\begin{matrix} m m \end{matrix}) =

\frac{1}{1.2} + \frac{1}{2.3} + \frac{1}{3.4} + . . . . + . . . . \frac{1}{n (n + 1)}

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