If mean and standard deviation of 5 observations x1,x2,x3,x4,x5 are 10 and 3, respectively, then the variance of 6observations x1,x2,....,x5 and −50 is equal to :
A
582.5
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B
507.5
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C
586.5
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D
509.5
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Solution
The correct option is A507.5 →x=10⇒∑5i=1xi=50 S.D.=√∑5i=5x2i5−(¯¯¯x)2=8 ⇒∑5i=1(xi)2=109 Variance =∑5i=1(xi)2+(−50)26−(∑5i=1xi−506) =507.5