If Michael Jordan has a vertical leap of $1.29 m$ , then what is his take off speed?

5.03 m / s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5.3 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.03 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7.03 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $5.03 m / s$
Vertical leap $h = 1.29 m$
Take off speed $v = \sqrt{2 g h}$
$⟹ v = \sqrt{2 \times 9.8 \times 1.29} = 5.03 m / s$

Suggest Corrections

Similar questions

If Michael Jordan has a vertical leap of 1.29 m, then what is his take off speed and his hang time (total time to move upwards to the peak and then return to the ground)?

Michael Jordan has a vertical leap of 1.25 m, what is his take-off speed and for how much time he will be in the air? Take a = 10 m/s² downwards.

Q. If Michael Jordan has a vertical leap of

1.29 m

, then what is his hang time (total time to move upwards to the peak and then return to the ground)?

Michael Jordan has a vertical leap of 1.25 m, what is his takeoff speed and for how much time he will be in the air? Take $g = 10 m s^{- 2}$ .

Michael Jordan has a vertical leap of 1.25 m, what is his takeoff speed and for how much time he will be in the air?
Take a = 10 m/s² downwards.

Join BYJU'S Learning Program

If Michael Jordan has a vertical leap of 1.29m, then what is his take off speed?

The correct option is A 5.03m/sVertical leap h=1.29 mTake off speed v=√2gh⟹ v=√2×9.8×1.29=5.03 m/s

If Michael Jordan has a vertical leap of $1.29 m$ , then what is his take off speed?

The correct option is A $5.03 m / s$
Vertical leap $h = 1.29 m$
Take off speed $v = \sqrt{2 g h}$
$⟹ v = \sqrt{2 \times 9.8 \times 1.29} = 5.03 m / s$