If minimum wavelength obtained in X-ray tube is $2.5 x 10$ for this minimum wavelength the minimum operating voltage of the tube should be-

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Solution

As you should know, the problem is referring to pm wavelengths.

So, $λ = 30 \times 10^{- 12} 10 m$

We take the formula that says:

$λ = 30 \times 10^{- 12} 10 m$

$λ_{m i n} = \frac{1.24 \times 10^{- 6} v . m}{V_{m a x}},$ then

$V_{m a x} = \frac{1.24 \times 10^{- 6} v . m}{λ_{m i n}},$ making the values substitution

$V_{m a x} = \frac{1.24 \times 10^{- 6} v . m}{30 \times 10^{- 12} m}$

$V_{m a x} = 4.13 \times 10^{4} v$

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If minimum wavelength obtained in X-ray tube is 2.5x10 for this minimum wavelength the minimum operating voltage of the tube should be-

As you should know, the problem is referring to pm wavelengths. So, λ=30×10−1210m We take the formula that says: λ=30×10−1210m λmin=1.24×10−6v.mVmax, then Vmax=1.24×10−6v.mλmin, making the values substitution Vmax=1.24×10−6v.m30×10−12m Vmax=4.13×104v

If minimum wavelength obtained in X-ray tube is $2.5 x 10$ for this minimum wavelength the minimum operating voltage of the tube should be-