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Question

If modular ratio is 'm', effective depth is D and stress ratio is 'r' (r=σstσcbc), the depth of neutral axis of a balanced section is

A
(mmr)×D
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B
(mm+r)×D
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C
(m+rm)×D
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D
(mr)×D
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Solution

The correct option is B (mm+r)×D

From ΔOAB and ΔBFC
Depth of neutral axis,
xu=σcbcσcbc+σstmD=(mm+r)D

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