Question

If molecular weight of glucose-1-phosphate is 260 and its density is $1.5gmc{m}^{-3}$, what is the average volume occupied by a molecule of this compound?

• A. $4.3\times {10}^{-23}c{m}^3$
• B. $0.67c{m}^3$
• C. $0.17\times {10}^{-23}c{m}^3$
• D. $29\times {10}^{-23}c{m}^3$

Answer 1

Answer: (A)

$4.3\times {10}^{-23}c{m}^3$

We know Volume $=\frac{mass}{density}$

Volume of $1$ mole of glucose$-1-$phosphate $=\frac{260}{1.5}=173.333\frac{gm}{{cm}^3}$

Volume of one molecule $=\frac{173.333}{6.023\times {10}^{23}}\approx 29\times {10}^{-23}{cm}^3$

Ans :- Option D.