Question

If momentum is increased by $20$% then kinetic energy increased by

• A. $44$%
• B. $55$%
• C. $66$%
• D. $77$%

Answer 1

The correct option is A $44$%

Kinetic energy is given as $KE=\frac{p^2}{2}.m=\left(1/2m\right)P^2$=

Now $P=P+0.20$—→$KE=(P+0.20P{)}^2$

So,$(P+0.20P)\ast 2-P^2=0.44P^2$,the increase in KE.

Therefore,$0.44P^2/P^2=0.44=44$. the percentage increase in the KE

option A is correct