If momentum of an object is increased by $10$ % then its kinetic energy will increase by:

20

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21

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40

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Solution

The correct option is A $20$ %
KE= $\frac{p^{2}}{2 m}$
$\frac{Δ K E}{K E} \times 100 = 2 \frac{Δ p}{p} \times 100 = 2 \times 10 = 20$ %

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