If μs and μk represent the coefficient of static and kinetic friction respectively with appropriate suffixes for the two bodies shown, find the acceleration of the system [ Take g=10m/s2]
A
10m/s2
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B
20m/s2
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C
15.5m/s2
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D
Zero
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Solution
The correct option is D Zero FBD of the blocks,
The maximum (limiting) frictional force on this 5kg block fmax1=μs1N1=0.6×50=30N
The maximum frictional force on this 2kg block fmax2=μs2N2=0.5×2×10=10N Total frictional force on this 5kg and 2kg block will be =40N FBD of 3kg block
The maximum force due to 3kg block is T2=30N
Since the applied force T2<fmax1+fmax2, system will remain stationary.