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Question
If (n+1)!=12(n−1)!, then the value of n is
If (n+1)!=12(n−1)!, then the value of n is
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Solution
The correct option is B 3
(n+1)!=12(n−1)!⇒(n+1)×n×(n−1)!=12×(n−1)!⇒n(n+1)=12⇒n2+n−12=0⇒(n+4)(n−3)=0⇒n=3 (∵n can't be negative)
(n+1)!=12(n−1)!⇒(n+1)×n×(n−1)!=12×(n−1)!⇒n(n+1)=12⇒n2+n−12=0⇒(n+4)(n−3)=0⇒n=3 (∵n can't be negative)
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