If n1,n2 and n3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by
A
1n=1n1+1n2+1n3
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B
1√n=1√n1+1√n2+1√n3
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C
√n=√n1+√n2+√n3
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D
n=n1+n2+n3
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Solution
The correct option is A1n=1n1+1n2+1n3 n1=12l1√Tμ n2=12l2√Tμ n3=12l3√Tμ n=12l√Tμ l=l1+l2+l3 1n=1n1+1n2+1n3