If n1,n2,n3 are the three fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency 'n' of the string is given by
A
√n=√n1+√n2+√n3
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B
1√n=1√n1+1√n2+1√n3
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C
n=n1+n2+n3
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D
1n=1n1+1n2+1n3
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Solution
The correct option is C1n=1n1+1n2+1n3 Total length of string is l=l1+l2+l3 but f∝1l ⇒1f=1f1+1f2+1f3