CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If n > 1, the value of 1log2n+1log3n+....+1log53n is


A

1log53!n

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1logn!53

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

None of these.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

1log53!n


The given expression is equal to logn2+logn3+...logn53=logn53!=1log53!n


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Laws of Logarithms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon