If n=5, then c0n2+c1n2+c2n2+..+c5n2
250
254
245
252
258
Explanation for correct option
Given n=5
∴c0n2+c1n2+c2n2+..+c5n2=c052+c152+c252+c352+c452+c552∵n=5=5!0!5-0!2+5!1!5-1!2+5!2!5-2!2+5!3!5-3!2+5!4!5-4!2+5!5!5-5!2∵cmn=n!m!n-m!=12+52+102+102+52+1=1+25+100+100+25+1=252
Hence, option(D) i.e. 252 is correct