If n A - 120- NB - 250 and n A - B - 52- then find nA- B

The correct option is A 302 n(A B)=n(A) n(A∩ B) ⇒ 52=120 n(A∩ B) ⇒ n(A∩ B)=120 52=68 Now #160; n(A∪ B)=n(A)+n(B) n(A∩ B) =120+25 ...

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Properties of Set Operation

If n A = 120,...

Question

If n (A) = 120, N(B) = 250 and n (A - B) = 52, then find $n (A \cup B)$

302

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250

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368

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None of the above

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A = {2, 4, 6, 8, . . .}

B = {3, 6, 9, 12, . . .}

n (A) = 200, n (B) = 250

n (A) = 30

n (B) = 40

n (A \cup B) = 52

n (A \cap B)

n (A) = 40, n (B) = 27

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) = 52

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n (A - B)

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n (A) = 300

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n (A \cap B) = 100

n (A^{^{'}} \cap B^{^{'}})

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