If nA - 50- nA - B - 80- nA - B - 30- then nB - A -

N(A ∪ B) = n(A) + n(B) – n(A ∩ B) ⇒ n(B) = 80 + 30 − 50 = 60 ∴ n(B – A) = n(B) – n(A ∩ B) = 60 − 30 = 30 ...

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Difference of Sets

If nA = 50, n...

Question

If $n (A) = 50, n (A \cup B) = 80, n (A \cap B) = 30$ , then $n (B - A) =$

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