If N a - an - n - N - then N 3- N 4-A- N 7B- N 3C- N 4D- N 12

The correct option is D N12 N_3 ∩ N_4 = {3,6,9,12,15 ……}∩{4,8,12,16,20, ……}= {12,24,36 ……} = N_12 [∵ 3,4 are relatively prime number ] ...

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Standard VI

Mathematics

HCF

If N a = an :...

Question

If $N_{a} = {a n : n \in N}$ , then $N_{3} \cap N_{4}$ =

N₇

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N₁₂

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N₃

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N₄

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Solution

The correct option is B
N₁₂

\( N_3 \cap N_4 = \{3,6,9,12,15 \ldots \ldots\} \cap \{4,8,12,16,20, \ldots \ldots\}

$= {12, 24, 36 \dots \dots} = N_{12}$

[ $∵$ 3,4 are relatively prime number ]

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If Na={an:n∈N} , then N3∩N4 =

The correct option is B N12 \( N_3 \cap N_4 = \{3,6,9,12,15 \ldots \ldots\} \cap \{4,8,12,16,20, \ldots \ldots\} ={12,24,36……}=N12 [∵ 3,4 are relatively prime number ]

If $N_{a} = {a n : n \in N}$ , then $N_{3} \cap N_{4}$ =

The correct option is B
N₁₂

\( N_3 \cap N_4 = \{3,6,9,12,15 \ldots \ldots\} \cap \{4,8,12,16,20, \ldots \ldots\}

$= {12, 24, 36 \dots \dots} = N_{12}$

[ $∵$ 3,4 are relatively prime number ]