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Standard XII

Chemistry

Atomic Size and Electronegativity

If nA × B=200...

Question

If n (A × B) = 200 and n(A) = 50, then the number of elements in P(B) is _______ .

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Solution

Given n (A × B) = 200
n(A) = 50
Since n(A × B) = n(A) n(B)
⇒ 200 = n(A) n(B)
i.e n(B) = $\frac{200}{5} = 4$
i.e number of elements of B are 4
i.e number of elements in P(B) = 2⁴

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If n (A × B) = 200 and n(A) = 50, then the number of elements in P(B) is _______ .

Given n (A × B) = 200 n(A) = 50 Since n(A × B) = n(A) n(B) ⇒ 200 = n(A) n(B) i.e n(B) = 2005 = 4 i.e number of elements of B are 4 i.e number of elements in P(B) = 24

Given n (A × B) = 200
n(A) = 50
Since n(A × B) = n(A) n(B)
⇒ 200 = n(A) n(B)
i.e n(B) = $\frac{200}{5} = 4$
i.e number of elements of B are 4
i.e number of elements in P(B) = 2⁴