If NA is the Avogadro’s number, then the number of valence electrons in 4.2 g of nitride ions (N3−) is:
Step 1:
Moles of nitride ion ⇒given massmolar mass
⇒4.214=0.3 NA nitride ions.
Step 2:
The number of valence electrons in an nitride ion =8 (5+3 due to the charge)
The number of valence electrons in 4.2 g of nitride ions ⇒8×0.3NA=2.4NA
Hence, option (C) is correct.