If 'n' electrons flow through a cross-section of a conductor in time t and charge on an electron is 'e', then the current in the conductor would be :

\frac{n e}{t}

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\frac{n e^{2}}{t}

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\frac{e}{t}

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\frac{n}{e t}

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Solution

The correct option is A $\frac{n e}{t}$
Consider a conductor of length of $L$ and cross sectional area $A$ .
When an electric field $E$ is applied across it, the electrons are drifted opposite to the applied field.
Volume of a conductor $= L A = 1$ in this case.
Let $n$ be the number of free electrons per unit volume of conductor.
Total charge on all the electrons in the conductor $= n L A e$
where, $e$ is the charge of each electron.
$\Rightarrow q = n L A e = n e A L$

But current, $I = \frac{q}{t} = \frac{n e A L}{t} = \frac{n e}{t} a s A L = 1$

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