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Question

If nϵ N,72n+23n3 is always divisible by


A
25
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B
35
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C
45
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D
None of these
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Solution

The correct option is B 25
Putting n=1 in 72n+23n3.3n1
then, nϵ N,72n+23n3.3n1
72×1+23×13.333
72+20.30=49+1=50        ......(i)
Also,n=2
72×2+23×2.321=2401+24=2425      (ii)
From (i) and (ii) it is always divisible by 25.

Mathematics

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