Question

If n equal resistances are first connected in series and then connected in parallel, the ratio of the maximum to the minimum resistance is

• A. n
• B. $\frac{1}{n^2}$
  
• C. $n^2$
  
• D. $\frac{1}{n}$

Answer 1

The correct option is C

$n^2$

Series resistance will be $R_s=nR$
Parallel resistance will be $R_p=\frac{R}{n}$
Therefore : $\frac{R_{max}}{R_{min}}=\frac{R_s}{R_p}=\frac{nR}{\left(\frac{R}{n}\right)}=n^2$