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Question

If n GMs be inserted between a and b, then the corresponding common ratio is

A
(ba)1/n+1
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B
(ab)1/n+1
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C
(ba)1/n
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D
(ab)1/n
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Solution

The correct option is A (ba)1/n+1
Let G1,G2,.............Gn are the G.Ms inserted between aandb and the common ration be r
G1=ar,G2=ar2,.........Gn=arn,b=arn+1
So using last term
rn+1=bar=(ba)1/n+1
Hence, option 'A' is correct.

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