If n harmonic means are inserted between 1 and r, then show that 1stmeannthmean=n+rnr++1
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Solution
We have calculated 1st harmonic mean in (2) of last question y1=(n+1)abnb+a ∴yn=nthH.M.=(n+1)abnb+a ∴1stmeannthmean=y1yn=b+nanb+a =r+n.1nr+1=n+rnr+1 [∴ a = 1, b = r]