If n is a positive integer, find the coefficient of x−1 in the expansion of (1+x)n(1+1x)n
We have
(1+x)n(1+1x)n=(1+x)n×(1+x)nxn=(1+x)2nxn
Coefficient of x−1 in the expansion of (1+x)n(1+1x)n
= coefficient of x−1 in the expansion of (1+x)n(1+1x)n= Coefficient of x−1in the expansion of (1+x)2nxn=Coefficient of(x−1×xn)in the expansion of(1+x)2n= Coefficient ofxn−1in the expansion of(1+x)2n=2nCn−1