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Question

If n is a positive integer, find the coefficient of x1 in the expansion of (1+x)n(1+1x)n

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Solution

We have
(1+x)n(1+1x)n=(1+x)n×(1+x)nxn=(1+x)2nxn
Coefficient of x1 in the expansion of (1+x)n(1+1x)n
= coefficient of x1 in the expansion of (1+x)n(1+1x)n= Coefficient of x1in the expansion of (1+x)2nxn=Coefficient of(x1×xn)in the expansion of(1+x)2n= Coefficient ofxn1in the expansion of(1+x)2n=2nCn1


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