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Question

If n is a positive integer, then prove that |Im(zn)|n|Im(z)||z|n1.

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Solution

Let z=r.eiθ
Hence zn=rn.einθ
Hence Im(zn) =rn.sin(nθ)
Now, n|Im(z)|.|zn1| =n|rsinθ|.|zn|.1|z|
=nrn|sinθ|
Now
n|sinθ||sin(nθ)| for n1
Hence the above inequality is true.

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