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Question

If n is an integer greater than 1, then anC1(a1)+nC2(a2)+....+(1)n(an) is equal to

A
a
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B
0
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C
a2
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D
2n
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Solution

The correct option is A 0
anC1(a1)+nC2(a2)+....+(1)n(an)
=anC1a+nC1+nC2a2 nC2+....+(1)na(1)nn nCn
=a{C0C1+C2C3+......(1)nCn}+{C12C2+3C3......(1)nn.Cn}
=a.0+0=0

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