If N is Avogadro's number, the number of molecules in 6 g of hydrogen at NTP is

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Solution

We know that
Number of moles =
$\frac{m a s s}{M o l a r m a s s}$
$M a s s = 6 g r a m s$
$M o l a r m a s s o f h y d r o g e n = 2$
$H e n c e n u m b e r o f m o l e s = \frac{6}{2} = 3 m o l e s$
$N u m b e r o f m o l e c u l e s = N u m b e r o f m o l e s \times A v o g a d r o^{'} s N u m b e r (N)$
$N u m b e r o f m o l e c u l e s = 3 \times N$
$H e n c e n u m b e r o f m o l e c u l e s = 3 N$

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