If n is even and the value of n C r is maximum- then r -A- n-2B- n-1-2C- n-1-2D- n - 4

The correct option is A It is obvious.r=n/2 ...

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Integration

If n is even ...

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If n is even and the value of $^{n} C_{r}$ is maximum, then r =

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n/4

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n - 1 \sum r = 0 \frac{^{n} C_{r}}{^{n} C_{r} +^{n} C_{r + 1}}

(2 \leq r \leq n),

^{n} C_{r} + 2 \cdot^{n} C_{r + 1} +^{n} C_{r + 2}

n \sum r = 1 \frac{r^{n} C_{r}}{^{n} C_{r - 1}}

\sum_{r = 0}^{n - 1} \frac{^{n} C_{r}}{^{n} C_{r} +^{n} C_{r + 1}}

The mean of 1, 2, 3, 4 ...n is given by

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