If n is even positive integer, then the condition that the greatest term in the expansion of (1+x)n may also have the greatest coefficient is
A
nn+2<x<n+2n
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B
nn+1<x<n+1n
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C
n+1n+2<x<n+2n+1
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D
n+2n+2<x<n+3n+2
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Solution
The correct option is Ann+2<x<n+2n For greatest term we have n2<n+11+|x|<n2+1 ⇒n2<n+11+x and n+11+|x|≤n2+1 ⇒1+x<n+1n/2 and n+1n2+1−1≤x ⇒x<n+1−n2n2 and n+1−n2−1n+22≤x ⇒x<n+2n and n+22≤x ∴nn+2<x<n+2n