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Question

If n is odd positive integer and (1+x+x2+x3)n=r=03narxr then a0+a1+a2+.......a3n is equal to


A

4n

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B

1

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C

-1

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D

0

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Solution

The correct option is D

0


Explanation for correct answer

Simplify the given equation,

(1+x+x2+x3)n=r=03narxr

Put x=-1

(1-1+1-1)=r=03narxr

0=a0+a1+a2+.......a3n

Hence, option D is the answer.


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