If n is odd positive integer and (1+x+x2+x3)n=∑r=03narxr then a0+a1+a2+.......a3n is equal to
4n
1
-1
0
Explanation for correct answer
Simplify the given equation,
(1+x+x2+x3)n=∑r=03narxr
Put x=-1
⇒(1-1+1-1)=∑r=03narxr
⇒0=a0+a1+a2+.......a3n
Hence, option D is the answer.