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Question

If n is odd then value of s=c1c02c2c1+3c3c2 ... upto n terms is

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Solution

nCrnCr1=nr+1r
S=C1C02C2C1+3C3C2+......n terms
=n1+112n2+12+3n3+13+....n terms
=n(n1)+(n2)+.......n terms
Let n=1,S=1=n
n=3,S=n1
n=5,S=n2
n=n,S=nn12
=2nn+12=n+12

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