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Question

If n is taken as 'n'th number, what is the expression for the given sequence
2, 5, 8, 11 ....... ?

A
3n - 1
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B
3n
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C
3n + 1
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D
3n + 2
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Solution

The correct option is A 3n - 1
In the given sequence of numbers,

1st number = 3×0 + 2
2nd number = 3×1 + 2 = 5
3rd number = 3×2 + 2 = 8
4th number = 3×3 + 2 = 11
. .
. .
. .
. .
. .
nth number = 3×(n1) + 2
= 3n - 3 + 2
= 3n - 1

The expression for the sequence is 3n - 1.

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